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NEW QUESTION: 1
You administer a Microsoft SQL Server 2012.
A process that normally runs in less than 10 seconds has been running for more than an hour.
You examine the application log and discover that the process is using session ID 60.
You need to find out whether the process is being blockeD.
Which Transact-SQL statement should you use?
A. DBCC INPUTBUFFER (60)
B. EXEC sp_who 60
C. EXEC sp_helpdb 60
D. SELECT * FROM sys.dm_exec_sessions WHERE sessionjd = 60
Answer: B
Explanation:
http://msdn.microsoft.com/en-us/library/ms174313.aspx http://msdn.microsoft.com/en-us/library/ms176013.aspx http://msdn.microsoft.com/en-us/library/ms178568.aspx http://msdn.microsoft.com/en-us/library/ms187730.aspx
NEW QUESTION: 2
The Motivation/Hygiene Theory (1959) is attributed to which of the following researchers?
A. Abraham Maslow
B. Clayton Alderfer
C. Victor Vroom
D. Fredrick Herzberg
Answer: D
Explanation:
Explanation: The Motivation/Hygiene Theory of 1959, which focuses on raising the value of a job in the eyes of the employee, is attributed to Fredrick Herzberg. Clayton Alderfer is responsible for the ERG Theory of 1969; Victor Vroom is credited with the Expectancy Theory of 1964; Abraham Maslow is credited with the Hierarchy of Needs Theory of 1954.
NEW QUESTION: 3
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, bei denen die gleichen oder ähnliche Antwortmöglichkeiten verwendet werden. Eine Antwortauswahl kann für mehr als eine Frage in der Reihe richtig sein. Jede Frage ist unabhängig von den anderen Fragen in dieser Reihe. In einer Frage angegebene Informationen und Details gelten für diese Frage.
Sie haben eine Datenbank für ein Bankensystem. Die Datenbank enthält zwei Tabellen mit den Namen tblDepositAcct und tblLoanAcct, in denen Einlagen- und Darlehenskonten gespeichert sind. Beide Tabellen enthalten folgende Spalten:
Sie müssen die Gesamtzahl der Kunden ermitteln, die entweder Einlagenkonten oder Darlehenskonten haben, jedoch nicht beide Kontotypen.
Welche Transact-SQL-Anweisung sollten Sie ausführen?
A. SELECT COUNT (DISTINCT L.CustNo) VON tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
B. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
C. SELECT COUNT (DISTINCT D.CustNo) FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
D. SELECT COUNT (DISTINCT COALESCE (D.CustNo, L.CustNo)) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWhere
E. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
F. SELECT COUNT (*) FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
G. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
H. SELECT COUNT (*) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
Answer: D
Explanation:
Explanation
SQL Server provides the full outer join operator, FULL OUTER JOIN, which includes all rows from both tables, regardless of whether or not the other table has a matching value.
Consider a join of the Product table and the SalesOrderDetail table on their ProductID columns. The results show only the Products that have sales orders on them. The ISO FULL OUTER JOIN operator indicates that all rows from both tables are to be included in the results, regardless of whether there is matching data in the tables.
You can include a WHERE clause with a full outer join to return only the rows where there is no matching data between the tables. The following query returns only those products that have no matching sales orders, as well as those sales orders that are not matched to a product.
USE AdventureWorks2008R2;
GO
-- The OUTER keyword following the FULL keyword is optional.
SELECT p.Name, sod.SalesOrderID
FROM Production.Product p
FULL OUTER JOIN Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IS NULL
OR sod.ProductID IS NULL
ORDER BY p.Name ;
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx