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NEW QUESTION: 1
Which of these are examples of a value in a sparse vector? (Select 2 answers.)
A. [0, 1]
B. [1, 0, 0, 0, 0, 0, 0]
C. [0, 5, 0, 0, 0, 0]
D. [0, 0, 0, 1, 0, 0, 1]
Answer: A,B
Explanation:
Categorical features in linear models are typically translated into a sparse vector in which each possible value has a corresponding index or id. For example, if there are only three possible eye colors you can represent 'eye_color' as a length 3 vector: 'brown' would become [1, 0, 0], 'blue' would become [0, 1, 0] and
'green' would become [0, 0, 1]. These vectors are called "sparse" because they may be very long, with many zeros, when the set of possible values is very large (such as all English words).
[0, 0, 0, 1, 0, 0, 1] is not a sparse vector because it has two 1s in it. A sparse vector contains only a single
1.
[0, 5, 0, 0, 0, 0] is not a sparse vector because it has a 5 in it. Sparse vectors only contain 0s and 1s.
Reference: https://www.tensorflow.org/tutorials/linear#feature_columns_and_transformations

NEW QUESTION: 2
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, bei denen die gleichen oder ähnliche Antwortmöglichkeiten verwendet werden. Eine Antwortauswahl kann für mehr als eine Frage in der Reihe richtig sein. Jede Frage ist unabhängig von den anderen Fragen in dieser Reihe. In einer Frage angegebene Informationen und Details gelten nur für diese Frage.
Sie haben eine Datenbank mit den Tabellen Customer_CRMSystem und Customer_HRSystem. Beide Tabellen haben folgende Struktur:

Die Tabellen enthalten die folgenden Datensätze:
Customer_CRMSystem

Customer_HRSystem

Datensätze, die Nullwerte für CustomerCode enthalten, können durch CustomerName eindeutig identifiziert werden.
Sie müssen Kunden anzeigen, die in beiden Tabellen aufgeführt sind und über einen korrekten Kundencode verfügen.
Welche Transact-SQL-Anweisung sollten Sie ausführen?

A. Option D
B. Option B
C. Option C
D. Option A
E. Option E
Answer: D
Explanation:
Erläuterung
Wenn sich in den Spalten der zu verbindenden Tabellen Nullwerte befinden, stimmen die Nullwerte nicht überein.
Das Vorhandensein von Nullwerten in einer Spalte aus einer der Tabellen, die verknüpft werden, kann nur mithilfe eines Outer-Joins zurückgegeben werden (sofern die WHERE-Klausel keine Nullwerte ausschließt).
Referenzen: https://technet.microsoft.com/en-us/library/ms190409(v=sql.105).aspx

NEW QUESTION: 3
共有を呼び出すためにモバイルアプリケーションに必要なシークレットを保存するようにクラウドサービスを構成する必要があります。
ソリューションに何を含める必要がありますか？回答するには、回答時に適切なオプションを選択してください。注：
それぞれの正しい選択は1ポイントの価値があります。

Answer:
Explanation:

Explanation

Every request made against a storage service must be authorized, unless the request is for a blob or container resource that has been made available for public or signed access. One option for authorizing a request is by using Shared Key.
Scenario: The mobile applications must be able to call the share pricing service of the existing retirement fund management system. Until the system is upgraded, the service will only support basic authentication over HTTPS.
The investment planning applications suite will include one multi-tier web application and two iOS mobile application. One mobile application will be used by employees; the other will be used by customers.
References: https://docs.microsoft.com/en-us/rest/api/storageservices/authorize-with-shared-key