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NEW QUESTION: 1
Your company has a virtualization environment that contains the virtualization hosts shown in the following table.
The virtual machines are configured as shown in the following table.
All the virtual machines use basic disks. VM1 is protected by using BitLocker Drive Encryption (BitLocker).
You plan to migrate the virtual machines to Azure by using Azure Site Recovery.
You need to identify which virtual machines can be migrated.
Which virtual machines should you identify for each server? To answer, select the appropriate options in the answer area.
NOTE: Each correct selection is worth one point.
Answer:
Explanation:
Explanation:
Incorrect Answers:
VM1 cannot be migrates as it has BitLocker enabled.
VM2 cannot be migrates as the OS disk on VM2 is larger than 2TB.
VMC cannot be migrates as the Data disk on VMC is larger than 4TB.
References:
https://docs.microsoft.com/en-us/azure/site-recovery/hyper-v-azure-support-matrix#azure-vm-requirements
NEW QUESTION: 2
The 802.11 series of standards calls for use of a Traffic Indication Map (TIM) and a Delivery Traffic Indication Message (DTIM). Which of the following is true regarding the TIM and DTIM in an infrastructure BSS?
A. The DTIM is used in 802.11a and 802.11g Beacons whereas the TIM is used only in
802.11b Beacons. The DTIM purpose is to allow for higher rates of Beacon broadcasting and thus raise overall data rates in OFDM based systems.
B. The first Beacon sent during a CFP must contain a DTIM
C. The TIM and DTIM are both part of the Beacon management frame and are both sent in every Beacon for the purpose of announcing the modulation type and supported rate set of the access point.
D. The DTIM parameters are part of each Beacon's TIM Information Element, and they are used to indicate queued broadcast/multicast data to client stations using power management features in the BSS.
E. A DTIM period of 0 means that every TIM is a DTIM.
F. The TIM is a field in the Beacon Management frame that holds a map of every client station associated to an access point. It is used for broadcast traffic delivery.
Answer: B,D
NEW QUESTION: 3
You are profiling a frequently used database table named UserEvents. The READ_COMMITED_SNAPSHOT database option is set to OFF.
In the trace results, you observe that lock escalation occurred for one stored procedure even though the number of locks in the database did not exceed memory or configuration thresholds. Events details are provided in the following table:
You need to modify the uspDeleteEvents stored procedure to avoid lock escalation.
How should you modify the stored procedure? To answer, select the appropriate Transact-SQL segments in the answer area.
Answer:
Explanation:
Explanation
Delete up to 4000 rows at a time. Keep doing it until all rows have been deleted.
Note that @@ROWCOUNT returns the number of rows affected by the last statement.
References: https://msdn.microsoft.com/en-us/library/ms187316.aspx
NEW QUESTION: 4
Which pieces of code inserted independently into places marked 1 and 2 will cause the program to compile and display: 0 1 2 3 4 5 6 7 8 9? Choose all that apply.
#include <list>
#include <iostream>
using namespace std;
class A { int a; public:
A(int a){ this?>a=a;}
//insert code here 1
};
//insert code here 2
template<class T> void print(T start, T end) {
while (start != end) {
std::cout << *start << " "; start++;
}
}
int main() {
A t1[] ={ 1, 7, 8, 4, 5 };list<A> l1(t1, t1 + 5);
A t2[] ={ 3, 2, 6, 9, 0 };list<A> l2(t2, t2 + 5);
l1.sort();l2.sort();l1.merge(l2);
print(l1.begin(), l1.end());
print(l2.begin(), l2.end()); cout<<endl;
return 0;
}
A. place 1: operator int() { return a; }
B. place 1: bool operator < (const A & b) { return this?>a< b.a;}
C. place 1: operator int() { return a; }
bool operator < (const A & b) { return this?>a< b.a;}
D. place 1: bool operator < (const A & b) { return this?>a< b.a;}
place 2: ostream & operator <<(ostream & c, const A & a) { c<<a.a; return c;}
E. place 1: bool operator < (const A & b) { return this?>a< b.a;}
friend ostream & operator <<(ostream & c, const A & a);
place 2: ostream & operator <<(ostream & c, const A & a) { c<<a.a; return c;}
Answer: A,C,E