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NEW QUESTION: 1
s cluster rf3 currently has 5 storage containers. storage pool: 15TB. you add 2 containers 'A' and 'B' with 1TB reserved capacity each. what's now the raw capacity of all seven containers?
A. original 5 containers: 3TB each; containers A and B: 4TB each
B. original 5 containers: 3TB each; containers A and B: 3TB each
C. original 5 containers:4TB each; containers A and B: 3TB each
D. original 5 containers: 4TB each; containers A and B: 4TB each
Answer: A

NEW QUESTION: 2
Suppose the Security Gateway hard drive fails and you are forced to rebuild it. You have a snapshot file stored to a TFTP server and backups of your Security Management Server. What is the correct procedure for rebuilding the Gateway quickly?
A. Reinstall the base operating system (i.e., SecurePlatform). Configure the Gateway interface so that the Gateway can communicate with the TFTP server. Reinstall any necessary Check Point products and previously applied hotfixes. Revert to the stored snapshot image, and install the Policy.
B. Reinstall the base operating system (i.e., SecurePlatform). Configure the Gateway interface so that the Gateway can communicate with the TFTP server. Revert to the stored snapshot image, and install the Security Policy.
C. Run the revert command to restore the snapshot, establish SIC, and install the Policy.
D. Run the revert command to restore the snapshot. Reinstall any necessary Check Point products. Establish SIC and install the Policy.
Answer: B

NEW QUESTION: 3
What is the highest normal form of the relation(s) shown in the exhibit?

A. STUDENT( Student_Number: integer NOT NULL Name:
variable length character string length 20 NOT NULL)
Primary Key StudenMMumber STU_CLASS(
Student_Number: integer NOT NULL Class_Num: integer
NOT NULL) Primary Key Student_Number CLASS(
Class_Num: integer NOT NULL Class_Name: integer NOT
NULL) Primary Key Class_Num
B. Boyce-Codd normal form
C. STUDENT( Student_Number: integer NOT NULL Name:
variable length character string length 20 NOT NULL)
Primary Key Student_Number CLASS( Class_Num: integer
NOT NULL Class_Name: integer NOT NULL) Primary Key
Class_Num Foreign Key Class_Num References STUDENT
D. First normal form
E. STUDENT( Student_Number: integer NOT NULL Name:
variable length character string length 20 NOT NULL)
Primary Key Student_Number CLASS( Class_Num: integer
NOT NULL Class_Name: integer NOT NULL) Primary Key
Class_Num
F. Third normal form
G. Second normal form
Answer: F