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NEW QUESTION: 1
A new instance/customer and new VMs are being added to the ACP 4200. As part of this procedure, additional VLANs are added to the ACP 4200.
What are these additional VLANs required to support?
A. A new instance of Avaya Orchestrator.
B. The new instances of iSCSI Storage Area Networks.
C. The new instances of Avaya Aura applications.
D. The new instances of ServerTech PDUs.
Answer: D

NEW QUESTION: 2
In a hotel reservation application, a form displays a list of hotels with available rooms based on the check-in and check-out dates entered by users.
How do you configure the form to refresh the hotel list whenever the check-in or check-out date changes?
A. Configure an action set on the hotel lijt display to refresh the section when the hotel list changes.
B. Display the hotel in an embedded section with a visible when condition.
C. Configure edit validates on the date fields to refresh the section when the date values change.
D. Configure action sets on the date fields to refresh the section when the date values change.
Answer: B

NEW QUESTION: 3
Which of the following areas is considered a strength of symmetric key cryptography when compared with asymmetric algorithms?
A. Security
B. Speed
C. Key distribution
D. Scalability
Answer: B

NEW QUESTION: 4



A. false \quarter\ . . \qtrlreport.txt
B. false \sales\quarter\ . . \qtrlreport.txt
C. true . . \ . . \ . . \ annualreport.txt
D. true \ . . \ . . \annualreport.txt
Answer: B
Explanation:
( richtig !! import java.nio.file.Path; import java.nio.file.Paths; ) original-Aufgabe war ( falsch >> import java.io.file.Path; import java.io.file.Paths; ) The relativize method that can be used to construct a relative path between two paths. relativize Path relativize(Path other) Constructs a relative path between this path and a given path. Parameters:other - the path to relativize against this path Returns:the resulting relative path, or an empty path if both paths are equal Note: Relativization is the inverse of resolution. This method attempts to construct a relative path that when resolvedagainst this path, yields a path that locates the same file as the given path. For18example, on UNIX, if this path is "/a/b" and the given path is "/a/b/c/d" then the resulting relative path would be"c/d". Where this path and the given path do not have a root component, then a relative path can beconstructed. A relative path cannot be constructed if only one of the paths have a root component. Where bothpaths have a root component then it is implementation dependent if a relative path can be constructed. If thispath and the given path are equal then an empty path is returned. For any two normalized paths p and q, where q does not have a root component,p.relativize(p.resolve(q)).equals(q) When symbolic links are supported, then whether the resulting path, when resolved against this path, yields apath that can be used to locate the same file as other is implementation dependent. For example, if this path is"/a/b" and the given path is "/a/x" then the resulting relative path may be "../x". If "b" is a symbolic link then isimplementation dependent if "a/b/../x" would locate the same file as "/a/x".