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NEW QUESTION: 1
展示を参照してください。ジュニアネットワークエンジニアが展示されている設定ファイルを用意しました。
インターフェイスfa0 / 1の計画されている設定に当てはまる文は2つありますか。 （2つ選んでください。）

A. fa0 / 1のIPアドレスは、それが存在するIPサブネットには無効です。
B. 2つのFastEthernetインターフェイスは、2つの外部シリアルインターフェイスにNATが設定されている必要があります。
C. インターネットホストは、表示されている設定ではDMZデバイスへの接続を開始できません。
D. fa0 / 1のIPアドレスがs0 / 0で使用されているスペースと重複しています。
E. DMZデバイスがインターネットにアクセスするためには、fa0 / 1でのアドレス変換は不要です。
Answer: C,E

NEW QUESTION: 2
universal containers (UC) has a Web -to -Case form on its Lightning Customer Community.
UC wants to separate Cases into the following product categories: Corrugated Paper, Plastic, Fiberboard, and Metal. UC has added a picklist field to store this data.
How can the Case be automatically placed in the correct queue upon submission?
A. Create Assignment Rules based on the picklist values to move Cases to a Queue.
B. Create Record Types for each picklist value and a Business Process to move each Case to the correct Queue.
C. Create Record Types for each picklist value and assign to each product team's profile.
D. Create an Escalation Rule entry for each picklist value and set to zero minutes.
Answer: A

NEW QUESTION: 3
Given an IP address of 192.168.1.42 255.255.255.248, what is the subnet address?
A. 192.168.1.8/29
B. 192.168.1.32/27
C. 192.168.1.48/29
D. 192.168.1.40/29
E. 192.168.1.16/28
Answer: D
Explanation:
248 mask uses 5 bits (1111 1000) 42 IP in binary is (0010 1010) The base subnet therefore is the lowest binary value that can be written without changing the output of an AND operation of the subnet mask and IP ... 1111 1000 AND 0010 1010 equals 0010 1000 - which is .40 /24 is standard class C mask. adding the 5 bits from the .248 mask gives /29