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NEW QUESTION: 1
Refer to the exhibit.

The following commands are executed on interface fa0/1 of 2950Switch.
2950Switch(config-if)# switchport port-security 2950Switch(config-if)# switchport port-security mac-address sticky 2950Switch(config-if)# switchport port-security maximum 1
The Ethernet frame that is shown arrives on interface fa0/1. What two functions will occur when this frame is received by 2950Switch? (Choose two.)
A. The MAC address table will now have an additional entry of fa0/1 FFFF.FFFF.FFFF.
B. Hosts B and C may forward frames out fa0/1 but frames arriving from other switches will not be forwarded out fa0/1.
C. Only frames from source 0000.00bb.bbbb, the first learned MAC address of 2950Switch, will be forwarded out fa0/1.
D. Only host A will be allowed to transmit frames on fa0/1.
E. All frames arriving on 2950Switch with a destination of 0000.00aa.aaaa will be forwarded out fa0/1.
F. This frame will be discarded when it is received by 2950Switch.
Answer: D,E
Explanation:
The configuration shown here is an example of port security, specifically port security using sticky addresses. You can use port security with dynamically learned and static MAC addresses to restrict a port's ingress traffic by limiting the MAC addresses that are allowed to send traffic into the port. When you assign secure MAC addresses to a secure port, the port does not forward ingress traffic that has source addresses outside the group of defined addresses. If you limit the number of secure MAC addresses to one and assign a single secure MAC address, the device attached to that port has the full bandwidth of the port.
Port security with sticky MAC addresses provides many of the same benefits as port security with static MAC addresses, but sticky MAC addresses can be learned dynamically. Port security with sticky MAC addresses retains dynamically learned MAC addresses during a link-down condition.

NEW QUESTION: 2
A developer wants to populate a data extension with the date of the most recent click for each subscriber. Which query would accomplish this?
A. SELECT c.SubscriberKey, c.eventDate FROM _Click c WHERE c.IsUnique = 1
B. SELECT c.SubscriberKey, MAX(c.eventDate) AS eventDate FROM _Click c GROUP BY c.SubscriberKey
C. SELECT TOP 1 c.SubscriberKey, c.eventDate FROM _Click c ORDER BY c.eventDate DESC
D. SELECT c.SubscriberKey, MIN (c.eventDate) AS eventDate FROM _Click c GROUP BY c.SubscriberKey
Answer: B

NEW QUESTION: 3
What is the present value today of these annual cash flows: $1,000, $2,000, $3,000? Assume the first cash flow occurs 1 year from today and an interest rate of 10% per year, compounded annually.
A. $2,754.32.
B. $4,104.98.
C. $4,815.93.
Answer: C
Explanation:
You could solve this question using 3 different compound interest problems, but it is easier to solve them using the calculator's cash flow functions.
On the BAII Plus, press CF 2nd CLRWork 0 ENTER DownArrow 1000 ENTER DownArrow DownArrow
2 000 ENTER DownArrow DownArrow 3000 ENTER DownArrow DownArrow 2nd Quit. Then press NPV
1 0 ENTER DownArrow CPT.
On the HP12C, press these keys: 0 BlueShift CFo 1000 BlueShift CFj 2000 BlueShift CFj 3000 BlueShift
CFj. Then press 10 i, YellowShift NPV.
The "DownArrow" represents the downward-pointing arrow on the top row of the BAII Plus keyboard.
Make sure that the BAII Plus has the P/Y value set to 1.

NEW QUESTION: 4

A. Option C
B. Option B
C. Option A
D. Option D
Answer: C
Explanation:
Reference:
http://www-03.ibm.com/systems/services/labservices/platforms/labservices_x.html