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NEW QUESTION: 1
Azure仮想マシンのデータ保護戦略を設計しています。すべての仮想マシンはマネージドディスクを使用します。次の要件を満たすソリューションを推奨する必要があります。
*暗号化キーの使用は監査されます。
*すべてのデータは常に保存時に暗号化されます。
* Microsoftではなく、暗号化キーを管理します
推奨事項には何を含める必要がありますか？
A. BitLockerドライブ暗号化（BitLocker）
B. クライアント側の暗号化
C. Azure StorageServiceの暗号化
D. Azureディスク暗号化
Answer: D
Explanation:
Reference:
https://docs.microsoft.com/en-us/azure/security/azure-security-disk-encryption-overview

NEW QUESTION: 2
Which are three key solutions and features of the cloud apps threat-centric solution? (Choose three.)
A. Cloud data loss prevention
B. CTD and Network Analytics
C. Cloud Remote Access
D. Remote access VPN
E. Cloud App Security
F. Accelerated threat response
Answer: A,E,F

NEW QUESTION: 3
Sie erstellen eine Tabelle mit den Spalten StudentCode, SubjectCode und Marks, um die Halbjahresnoten für die Schüler aufzuzeichnen. Die Tabelle enthält Noten von 50 Schülern für verschiedene Fächer.
Sie müssen sicherstellen, dass die folgenden Anforderungen erfüllt sind:
* Die Einstufung der Schüler muss anhand ihrer Durchschnittsnote erfolgen.
* Wenn ein oder mehrere Schüler den gleichen Durchschnitt haben, müssen diese Schüler den gleichen Rang erhalten.
* Aufeinanderfolgende Ränge müssen übersprungen werden, wenn derselbe Rang zugewiesen wird.
Welche Transact-SQL-Abfrage sollten Sie verwenden?
A. SELECT StudentCode AS Code, markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) ALS Rang
FROM StudentMarks) tmp
WO Rang = 1
B. SELECT StudentCode as Code,
NTILE (2) OVER (BESTELLUNG NACH AVG (Marks) DESC) AS-Wert
VON StudentMarks
GROUP BY StudentCode
C. SELECT StudentCode AS Code, Markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION NACH SubjectCode ORDER NACH Marks DESC) AS Rank
FROM StudentMarks) tmp
WO Rang = 1
D. SELECT StudentCode AS Code, Markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY ASC-Zeichen) AS Rank
FROM StudentMarks) tmp
WO Rang = 1
E. SELECT StudentCode as Code,
RANG () ÜBER (ORDER BY AVG (Marks) DESC) ALS Wert
VON StudentMarks
GROUP BY StudentCode
F. SELECT StudentCode AS Code, markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Markiert ASC) AS Rank
FROM StudentMarks) tmp
WO Rang = 1
G. SELECT ID, Name, Markierungen,
DENSE_RANK () ÜBER (ORDER BY Markiert DESC) ALS Rang
VON StudentMarks
H. SELECT StudentCode as Code,
DENSE_RANK () ÜBER (ORDER BY AVG (Marks) DESC) ALS Wert
VON StudentMarks
GROUP BY StudentCode
Answer: E
Explanation:
Referenz: http://msdn.microsoft.com/en-us/library/ms189798.aspx