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NEW QUESTION: 1
Identify the proper device for the second partition on the only SCSI drive on the system.
A. /dev/sd1p2
B. /dev/sd0a2
C. /dev/sda2
D. /dev/hda1
Answer: C
NEW QUESTION: 2
Which of the following options from the Select menu is used to increase the size of an existing selection?
A. Reselect
B. Deselect
C. Expand
D. Contract
Answer: C
NEW QUESTION: 3
Sie erwerben einen neuen Windows 10 Enterprise-Desktopcomputer. Sie haben vier externe USB-Festplatten.
Sie möchten mithilfe der vier USB-Laufwerke ein einzelnes Volume erstellen. Sie möchten, dass das Volume im Falle eines Ausfalls einer einzelnen USB-Festplatte erweiterbar, portabel und belastbar ist.
Sie müssen das erforderliche Volume erstellen.
Was tun?
A. Erstellen Sie über die Datenträgerverwaltung ein neues gestreiftes Volume.
B. Erstellen Sie in der Systemsteuerung einen neuen Speicherplatz auf 4 USB-Festplatten. Setzen Sie den Ausfallsicherheitstyp auf Parität.
C. Erstellen Sie in der Systemsteuerung einen neuen Speicherplatz auf 4 USB-Festplatten. Legen Sie den Ausfallsicherheitstyp auf Drei-Wege-Spiegel fest.
D. Erstellen Sie über die Datenträgerverwaltung ein neues übergreifendes Volume.
Answer: B
Explanation:
Erläuterung
Storage Spaces können mehrere Festplatten zu einer virtuellen Festplatte zusammenfassen. Um einen Speicherplatz zu erstellen, müssen Sie zwei oder mehr zusätzliche interne oder externe Laufwerke an Ihren Computer anschließen, um einen Speicherpool zu erstellen.
Sie können auch eine beliebig große logische Größe angeben. Wenn Ihr vorhandenes Laufwerk fast voll ist, zeigt Windows im Aktionscenter eine Benachrichtigung an, in der Sie aufgefordert werden, zusätzlichen physischen Speicherplatz hinzuzufügen. Durch Auswahl des Paritätsausfallsicherheitstyps kann Windows Paritätsinformationen mit den Daten speichern und Sie so vor einem Ausfall eines einzelnen Laufwerks schützen.
NEW QUESTION: 4
Given the network diagram.
Which address would successfully summarize only the networks seen?
A. 192.168.8.0/20
B. 192.168.0.0/24
C. 192.168.12.0/20
D. These networks cannot be summarized.
E. 192.168.16.0/21
F. 192.168.8.0/21
Answer: F
Explanation:
let's suppose it is a /20 then we would have addresses from 192.168.0.1 to 192.168.15.255 Now let's suppose it is a /21 then we would have addresses from 192.168.8.1 to
192.168.15.255
So both summaries encompass the networks we want to summarize but the second one is the most restrictive one as it only encompasses the networks we were asked to summarize and not others so it is the correct summary.
In fact just count the number of subnets which is 8 and find the exponent of 2 which is 8, that gives you 3 and to find out the summary mask just do /24 - 3 = /21.
if you make it in binary you'll find out the answer too:
the interesting octet is 3rd one so let's convert in binary.
8 0000 1000
9 0000 1001
1 0 0000 1010
1 1 0000 1011
1 2 0000 1100
1 3 0000 1101
1 4 0000 1110
1 5 0000 1111
I've bolded the bits in common there are 5 so 16+5=21 which is mask and address is
1 92.168.8.0