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NEW QUESTION: 1
The EMPLOYEES table has these columns:
LAST NAME. VARCHAR2(35) SALARY. NUMBER(8, 2) HIRE_DATE. DATE
Management wants to add a default value to the SALARY column. You plan to alter the table by using this SQL statement:
ALTER TABLE EMPLOYEES MODIFY (SALARY DEFAULT 5000);
What is true about your ALTER statement?
A. All the rows that have a NULL value for the SALARY column will be updated with the value 5000.
B. Column definitions cannot be altered at add DEFAULT values for columns with a NUMBER data type.
C. Column definitions cannot be altered to add DEFAULT values.
D. A change to the DEFAULT value affects only subsequent insertions to the table.
Answer: D
Explanation:
A change to the DEFAULT value affects only subsequent insertions to the table. Existing rows will not be affected.
Incorrect Answers A:. Column definitions can be altered to add DEFAULT values.
C:. Column definitions can be altered to add DEFAULT values. It works for columns with a NUMBER data type also.
D:. A change to the DEFAULT value affects only subsequent insertions to the table. Existing rows will not be affected.
OCP Introduction to Oracle 9i: SQL Exam Guide, Jason Couchman, p. 219-224 Chapter 5: Creating Oracle Database Objects

NEW QUESTION: 2
HOTSPOT


Answer:
Explanation:

NEW QUESTION: 3
Betrachten Sie den folgenden Pseudocode:
1 Beginnen Sie
2 Lesezeit
3 Wenn die Zeit <12 ist, dann
4 Drucken (Uhrzeit, "am")
5 Endif
6 Wenn Zeit> 12 Dann
7 Drucken (Uhrzeit 12, "pm")
8 Endif
9 Wenn Zeit = 12 Dann
1 0 Drucken (Uhrzeit, "Mittag")
1 1 Endif
1 2 Ende
Wie viele Testfälle sind erforderlich, um eine 100-prozentige Entscheidungsabdeckung zu erreichen?
A. 0
B. 1
C. 2
D. 3
Answer: C
Explanation:
Erläuterung:
Die drei Entscheidungen sind aufeinanderfolgend und die Bedingungen schließen sich gegenseitig aus (wenn eine wahr ist, müssen die anderen falsch sein). Ein Testfall, bei dem die erste Entscheidung wahr ist, macht die zweite und dritte Entscheidung falsch und so weiter.
Testfall 1 (sagen wir Zeit = 6) würde also den Pfad Wahr, Falsch, Falsch ausüben, Testfall 2 (sagen wir Zeit = 15) würde den Pfad Falsch, Wahr, Falsch ausüben. Testfall 3 müsste Zeit sein
= 12. Diese Kombination erreicht eine 100-prozentige Entscheidungsabdeckung, da jede Entscheidung durch ihre wahren und ihre falschen Ergebnisse ausgeführt wurde.

NEW QUESTION: 4
A newly established CSP allows for drive shipping to upload new data into the environment.
Sensitive data on 40TB of storage needs to be transferred within one week.
Which of the following is the MOST efficient and secure method for shipment of the data to the CSP with minimal downtime?
A. Create a VPN between the sites and schedule data transfer during non-business hours.
B. Move the data to encrypted drives and use the CSP-certified shipping provider.
C. Copy the data to encrypted drives and use the CSP-certified shipping provider.
D. Compress and SFTP the data to the CSP.
Answer: B