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Simulation for the software version.
NEW QUESTION: 1
ルーターが100 kbpsを受け入れるSSHの量を制限する構成はどれですか。
A）
B）
C）
D）
A. オプションC
B. オプションA
C. オプションB
D. オプションD
Answer: A
Explanation:
CoPP protects the route processor on network devices by treating route processor
resources as a separate entity with its own ingress interface (and in some
implementations, egress also). CoPP is used to police traffic that is destined to the
route processor of the router such as:
+ routing protocols like OSPF, EIGRP, or BGP.
+ Gateway redundancy protocols like HSRP, VRRP, or GLBP.
+ Network management protocols like telnet, SSH, SNMP, or RADIUS.
Therefore we must apply the CoPP to deal with SSH because it is in the
management plane. CoPP must be put under "control-plane" command.
NEW QUESTION: 2
Capture automation helps organizations reduce manual labor costs by which of the following:
A. Lookups
B. Automatic document identification and extraction of data
C. Integration with FileNet P8, Content Manager 8.0 and Content Manager OnDemand repositories
D. Rulerunner Enterprise
Answer: B
Explanation:
Reference:http://www-01.ibm.com/software/data/content-management/offer/proddemo.html(see IBM capture, second last row of the table)
NEW QUESTION: 3
Refer to the exhibit.
Which values are correct for AP 2 to allow for efficient roaming?
A. Channel 6, SSID Sittingduck, BSSID 00:0a:0b:0c:0d:0e
B. Channel 6, SSID Sittingduck, BSSID 00:01:02:03:04:05
C. Channel 1, SSID Sittingduck, BSSID 00:01:02:03:04:05
D. Channel 1, SSID Sittingduck, BSSID 00:0a:0b:0c:0d:0e
Answer: A
NEW QUESTION: 4
A. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML RAW, ELEMENTS
B. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
C. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
D. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO
E. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
F. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML RAW
G. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO
H. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
Answer: H