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NEW QUESTION: 1
In HPE Smart Storage Administrator, what does the Wear Gauge parameter describe?
A. performance metrics for SSD drive
B. remaining expected lifetime of an SSD drive
C. availability level (MTBF) for an SSD drive
D. maximum number of SSD drives that can be installed in a system
Answer: B
Explanation:
Explanation/Reference:
Reference: https://community.hpe.com/hpeb/attachments/hpeb/itrc-264/148204/3/HP%20Smart%
20Storage%20Administrator%20User%20Guide.pdf
NEW QUESTION: 2
You are developing a web app that uses a REST interface to connect to Azure Storage with HTTPS. This app uploads and streams video content that can be accessed from anywhere in the world.
You have different storage requirements for each part of the app. A hierarchical namespace must be created.
Which storage services should you implement? To answer, select the appropriate services to the correct actions. Each service may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.
NOTE:Each correct selection is worth one point.
Answer:
Explanation:
Explanation
NEW QUESTION: 3
Sie erstellen eine Tabelle mit den Spalten StudentCode, SubjectCode und Marks, um die Halbjahresnoten für die Schüler aufzuzeichnen. Die Tabelle enthält Noten von 50 Schülern für verschiedene Fächer.
Sie müssen sicherstellen, dass die obere Hälfte der Schüler, geordnet nach ihren Durchschnittsnoten, den Rang 1 und die übrigen Schüler den Rang 2 erhalten.
Welche Transact-SQL-Abfrage sollten Sie verwenden?
A. SELECT StudentCode AS Code, Markiert AS Value FROM (SELECT StudentCode, Markiert AS Marks, RANXO OVER (PARTITION VON StudentCode ORDER VON Marks DESC) AS RankFROM StudentMarks) tmpWHERE Rank = 1
B. SELECT StudentCode as Code, NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS ValueFROM StudentMarksGROUP BY StudentCode
C. SELECT StudentCode AS Code, Markiert AS Value FROM (SELECT StudentCode, Markiert AS Marks, RANK () OVER (PARTITION NACH SubjectCode ORDER NACH Marks DESC) AS RankFROM StudentMarks) tmpWHERE Rank = 1
D. SELECT StudentCode AS Code, markiert AS Value FROM (SELECT StudentCode, markiert AS Marks, RANK () OVER (PARTITION NACH SubjectCode ORDER NACH Marks ASC) AS RankFROM StudentMarks) tmpWHERE Rank = 1
E. StudentCode als Code AUSWÄHLEN, DENSE_RANK () ÜBER (ORDER BY AVG (Marks) DESC) ALS ValueFROM StudentMarksGROUP BY StudentCode
F. SELECT StudentCode AS Code, Markiert AS Value FROM (SELECT StudentCode, Markiert AS Marks, RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS RankFROM StudentMarks) tmpWHERE Rank = 1
G. WÄHLEN SIE StudentCode als Code, RANK () ÜBER (ORDER BY AVG (Marks) DESC) ALS ValueFROM StudentMarksGROUP BY StudentCode
H. SELECT ID, Name, Markierungen, DENSE_RANK () OVER (ORDER BY Marks DESC) AS RankFROM StudentMarks
Answer: B