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NEW QUESTION: 1
Your customer has requirements for key mapping beyond the Unified Kep Mapping Service (UKMS) standard. Which configuration tasks must you perform?
There are 2 correct answers to this question.
A. Perform additional configuration in the workflow templates after extension for existing or creation of new business objects
B. Define key mapping in communication if you work with un harmonized keys in your system landscape.
C. Define key mapping when you use Flex Data Models.
D. Implement additional coding after extending existing or defining new business objects.
Answer: A,B
NEW QUESTION: 2
A manufacturing company plans to implement Dynamics 365 Field Service.
You need to determine which features are needed to meet the company's requirements.
Which features should you implement? To answer, drag the appropriate features to the correct requirements. Each feature may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.
NOTE: Each correct selection is worth one point.
Answer:
Explanation:
Reference:
https://docs.microsoft.com/en-us/dynamics365/field-service/overview
NEW QUESTION: 3
ルーターの仮想端末インターフェイスを保護するために何ができますか？ （2つ選択してください。）
A. アクセスリストを入力し、access-classコマンドを使用して仮想端末インターフェイスに適用します。
B. 仮想端末のパスワードとログインプロセスを設定します。
C. アクセスリストを作成し、access-groupコマンドを使用して仮想端末インターフェイスに適用します。
D. インターフェースを物理的に保護します。
E. インターフェイスを管理上シャットダウンします。
Answer: A,B
Explanation:
インターフェイスを管理上シャットダウンするのは無駄です。さらに、他のインターフェイスを介して誰かが仮想端末インターフェイスにアクセスできます-> Aは正しくありません。
「仮想」であるため、仮想インターフェイスを物理的に保護できません-> Bは正しくありません。
アクセスリストを仮想端末インターフェイスに適用するには、「access-class」コマンドを使用する必要があります。
「access-group」コマンドは、物理インターフェイスにアクセスリストを適用するためにのみ使用されます-> Cは正しくありません。 Eは正しいです。
仮想端末インターフェイスを保護する最も簡単な方法は、不正なログインを防ぐためにユーザー名とパスワードを設定することです-> Dは正しいです。
NEW QUESTION: 4
Siehe Ausstellung. Welche Adress- und Maskenkombination stellt eine Zusammenfassung der von EIGRP gelernten Routen dar?
A. 192.168.25.28 255.255.255.252
B. 192.168.25.0 255.255.255.240
C. 192.168.25.16 255.255.255.240
D. 192.168.25.16 255.255.255.252
E. 192.168.25.0 255.255.255.252
F. 192.168.25.28 255.255.255.240
Answer: C
Explanation:
The binary version of 20 is 10100.
The binary version of 16 is 10000.
The binary version of 24 is 11000.
The binary version of 28 is 11100.
The subnet mask is /28. The mask is 255.255.255.240.
Note:
From the output above, EIGRP learned 4 routes and we need to find out the summary of them:
+ 192.168.25.16
+ 192.168.25.20
+ 192.168.25.24
+ 192.168.25.28
-> The increment should bE. 28 ?16 = 12 but 12 is not an exponentiation of 2 so we must choose 16 (24). Therefore the subnet mask is /28 (=1111 1111.1111 1111.1111 1111.11110000) = 255.255.255.240 So the best answer should be 192.168.25.16 255.255.255.240