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NEW QUESTION: 1
When building an application, why might you use a tab set?
A. To group related fields for administrative purposes only
B. To better organize History Log data
C. To group related fields using custom HTML code
D. To group related fields into logical arrangements
Answer: C
NEW QUESTION: 2
Refer to the exhibit. Which effect of this Cisco ASA policy map is true?
A. The Cisco ASA logs SMTP sessions in clear text.
B. The server ends the SMTP session with a QUIT command if the algorithm or key length is insufficiently secure.
C. it prevents a STARTTLS session from being established.
D. The Cisco ASA is unable to examine the TLS session.
Answer: B
NEW QUESTION: 3
Refer to the exhibit.
Which three statements about the R1 configuration are true? (Choose three.)
A. The virtual circuit identifier is 1611 and the virtual circuit is down.
B. The targeted LDP session to the remote peer is up.
C. The local label for the circuit is 1611.
D. The virtual circuit identifier is 4006 and the virtual circuit is down.
E. The circuit is using MPLS VC type 4.
F. The local label for the circuit is 4006.
Answer: A,B,F
Explanation:
The number after the vc is the identifier, which is 1611 in this case. Here, the VC status is shown
as down.
As shown, the MPLS VC labels: local 4006, remote unassigned shows the local label used is
4006.
The targeted LDP session is up as verified by the "Signalling protocol: LDP, peer 172.16.12.70 up"
statement in the output.
NEW QUESTION: 4
<row OrderId="1" OrderDate="2000-01-01T00:00:00" Amount="3400.00" Name="Customer
A" Country="Australia" />
<row OrderId="2" OrderDate="2001-01-01T00:00:00" Amount="4300.00" Name="Customer
A" Country="Australia" />
Which Transact-SQL query should you use?
A. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
B. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML RAW
C. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO
D. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO
E. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML RAW, ELEMENTS
F. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId - Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
G. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
H. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
Answer: B
Explanation:
Reference: http://msdn.microsoft.com/en-us/library/bb510464.aspx