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NEW QUESTION: 1
Given the code fragment from three files:

Which code fragment, when inserted at line 2, enables the code to compile?

A. Option E
B. Option C
C. Option B
D. Option D
E. Option A
Answer: D

NEW QUESTION: 2
A security administrator is tasked with calculating the total ALE on servers. In a two year period of time, a company has to replace five servers. Each server replacement has cost the company $4,000 with downtime costing $3,000. Which of the following is the ALE for the company?
A. $10,000
B. $35,000
C. $7,000
D. $17,500
Answer: D

NEW QUESTION: 3
主要な金融システムへのインターフェースを開発しているチームが、ライブラリの1つにセキュリティ上の欠陥を発見しました。欠陥を修正するには、システムを大幅に再設計する必要があります。情報セキュリティ管理者は次に何をすべきですか？
A. 欠陥を修正するよう開発チームに指示します。
B. 適切な修復制御を設計するコンサルタントを雇います。
C. 事業主に影響を確認します。
D. 包括的なソースコードレビューを実施します。
Answer: C

NEW QUESTION: 4
View the exhibit and examine the structure of the EMPLOYEES table.
You want to display all employees and their managers having 100 as the MANAGER_ID.
You want the output in two columns: the first column would have the LAST_NAME of the managers and the second column would have LAST_NAME of the employees.
Which SQL statement would you execute?
A. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE e.manager_id = 100;
B. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE m.manager_id = 100;
C. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eWHERE m.employee_id = e.manager_id and AND e.manager_id = 100
D. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON e.employee_id = m.manager_idWHERE m.manager_id = 100;
Answer: A