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NEW QUESTION: 1
The following diagnostic output is displayed in the CLI:
diag firewall auth list
policy iD. 9, srC. 192.168.3.168, action: accept, timeout: 13427
user: forticlient_chk_only, group:
flag (80020): auth timeout_ext, flag2 (40): exact
group iD. 0, av group: 0
----- 1 listed, 0 filtered ------
Based on this output, which of the following statements is correct?
A. The client check that is part of an SSL VPN connection attempt failed.
B. Firewall policy 9 has endpoint compliance enabled but not firewall authentication.
C. This user has been associated with a guest profile as evidenced by the group id of 0.
D. An auth-keepalive value has been enabled.
Answer: B
NEW QUESTION: 2
Refer to the exhibit. PC1 pings PC2. What three things will CORE router do with the data that is received from PC1? (Choose three.)
A. CORE router will put the MAC address of the forwarding FastEthernet interface in the place of the source MAC address.
B. CORE router will replace the MAC address of PC2 in the destination MAC address of the frames.
C. The data frames will be forwarded out interface FastEthernet0/1 of CORE router.
D. CORE router will replace the destination IP address of the packets with the IP address of PC2.
E. CORE router will put the IP address of the forwarding FastEthernet interface in the place of the source IP address in the packets.
F. The data frames will be forwarded out interface FastEthernet1/0 of CORE router.
Answer: B,F
NEW QUESTION: 3
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server.
The database contains two tables that have the following definitions: Global customers place orders from several countries.
You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK() OVER (PARTITION BY CustomerID ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk FROM Customer c INNER JOIN Orders o ON c.CustomerID = o.CustomerID GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, RANK() OVER (PARTITION BY CustomerID ORDER BY OrderAmount DESC) AS Rnk FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID WHERE o.Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, COUNT(OrderAmount) DESC) AS OrderAmount FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, RANK() OVER (PARTITION BY CustomerID ORDER BY COUNT(OrderAmount) DESC) AS Rnk FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID WHERE o.Rnk = 1
Answer: D