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NEW QUESTION: 1
Click the Exhibit button.

Which type of security solution is shown in this exhibit?
A. inline security model
B. de-centralized model
C. centralized model
D. service chain model
Answer: D

NEW QUESTION: 2
Your Windows Communication Foundation (WCF) client application uses HTTP to communicate with the service.
You need to enable message logging and include all security information such as tokens and nonces in logged messages.
What should you do?
A. In the application configuration file, add the logKnownPii attribute to the message
logging diagnostics source and set the value of the attribute to true.
Generate the ContosoService class using the Add Service Reference wizard. Add a
reference to System.ServiceModel.Routing.dll.
Add the following code segment.
ContosoService client = new ContosoService();
SoapProcessingBehavior behavior = new SoapProcessingBehavior();
behavior.ProcessMessages = true;
client.Endpoint.Behaviors.Add(behavior);
B. In the machine configuration file, add the following XML segment to the
system.serviceModel configuration section.
<machineSettings enableLoggingKnownPii="true" />
In the application configuration file, add the logKnownPii attribute to the message logging
diagnostics source and set the value of the attribute to true. In the application configuration
file, add the following XML segment to the system.serviceModel configuration section
group.
<diagnostics>
<messageLogging logMessagesAtTransportLevel="true"/>
</diagnostics>
C. In the machine configuration file, add the following XML segment to the
system.serviceModel configuration section.
<machineSettings enableLoggingKnownPii="true" />
Generate the ContosoService class using the Add Service Reference wizard.
Add the following code segment.
ContosoService client = new ContosoService();
client.Endpoint.Behaviors.Add(new CallbackDebugBehavior(true));
D. In the application configuration file, add the following XML segment to the
system.serviceModel configuration section group.
<diagnostics>
<messageLogging logMessagesAtTransportLevel="true"
logEntireMessage="true" />
</diagnostics>
Answer: B

NEW QUESTION: 3
展示を参照してください。ネットワークの問題をトラブルシューティングするとき、ネットワークアナライザーはLANスイッチのポートf0 / 1に接続されます。このコマンドは、このポートでのBPDU送信を防ぐことができますか？

A. スパニングツリーリンクタイプは共有されていません
B. スパニングツリーPortFast bpduguardの有効化
C. スパニングツリーbpduguardのデフォルト
D. スパニングツリーportfast bpdufilterのデフォルト
Answer: D

NEW QUESTION: 4



A. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
B. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
C. CustNo
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo
F. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo
G. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
H. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
I. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
J. CustNoWHERE D.CustNo IS NULL
Answer: F
Explanation:
The RIGHT JOIN keyword returns all records from the right table (table2), and the matched records from the left table (table1). The result is NULL from the left side, when there is no match.
References: https://www.w3schools.com/sql/sql_join_right.asp