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NEW QUESTION: 1
Refer to the exhibit.

After configuring two interfaces on the HQ router, the network administrator notices an error message. What must be done to fix this error?
A. The address of the FastEthernet interface should be changed to 192.168.1.66
B. The serial interface must be configured first.
C. The serial interface must use the address 192.168.1.2
D. The subnet mask of the serial interface should be changed to 255.255.255.0
E. The subnet mask of the FastEthernet interface should be changed to 255.255.255.240
Answer: E
Explanation:
The IP address 192.168.1.17 255.255.255.0 specifies that the address is part of the
192.168.1.0/24 subnet
2 4 mask bits = 255.255.255.0
2 8 mask bits = 255.255.255.240
1 92.168.1.0/24 subnet has a host range of 192.168.1.1 to 192.168.1.254 (0 being network and 255 being broadcoast)
1 92.168.1.17/28 subnet has a host range of 192.168.1.17 to 192.168.1.30 (16 being network and 31 being broadcast)
1 92.168.1.65/28 subnet has a host range of 192.168.1.65 - 192.168.1.78 (64 being network and 79 being broadcast) if fa0/0 was left as /24, you can see that the host range includes the host range of
192.168.1.64/28 which conflicts. Simply speaking, you can't overlap the subnets. By changing the subnet mask of fa0/0 to 255.255.255.240, these networks would no longer overlap.

NEW QUESTION: 2
Refer to the exhibit. Host A can communicate with Host B but not with Hosts C or D How can the network administrator solve this problem?

A. Enable the VLAN trunking protocol on the switch.
B. Configure Hosts C and D with IP addresses in the 192.168.2.0 network.
C. Install a second switch and put Hosts C and D on that switch while Hosts A and B remain on the original switch.
D. Install a router and configure a route to route between VLANs 2 and 3.
Answer: D

NEW QUESTION: 3
Which of the following layers of the OSI model corresponds to the Host-to-Host layer of the TCP/IP model?
A. The presentation layer
B. The transport layer
C. The session layer
D. The application layer
Answer: B

NEW QUESTION: 4
Which NLS parameter can be used to change the default Oracle sort method from binary to linguistic for the SQL SELECT statement?
A. None of the above
B. NLS_LANG
C. NLS_COMP
D. NLS_SORT
Answer: A
Explanation:
Explanation/Reference:
Explanation:
Neither NLS_SORT nor NLS_COMP cannot change sorting from BINARY to LINGUISTIC. Because the NLS_SORT depends on NLS_COMP, if they are different, the sorting method will always be BINARY.
(Refer to NLS_SORT) The exact operators and query clauses that obey the NLS_SORT parameter depend on the value of the NLS_COMP parameter. If an operator or clause does not obey the NLS_SORT value, as determined by NLS_COMP, the collation used is BINARY.
The BINARY comparison is faster and uses less resources than any linguistic comparison but for text in a natural language, it does not provide ordering expected by users.
The value of NLS_SORT affects execution plans of queries. Because a standard index cannot be used as a source of values sorted in a linguistic order, an explicit sort operation must usually be performed instead of an index range scan. A functional index on the NLSSORT function may be defined to provide values sorted in a linguistic order and reintroduce the index range scan to the execution plan.
NLS_COMP specifies the collation behavior of the database session.